What is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses
SA=a^2+2a a^2/4 + h^2−−−−−−√
SA=2(wl+lh+hw)
SA=1/2ab+3(1/2lb)
SA=lw+1/2w4h^2+l^2−−−−−−−√+1/2l4^h^2+w^2−−−−−−−√
Responses
SA=a^2+2a a^2/4 + h^2−−−−−−√
SA=2(wl+lh+hw)
SA=1/2ab+3(1/2lb)
SA=lw+1/2w4h^2+l^2−−−−−−−√+1/2l4^h^2+w^2−−−−−−−√