hat is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses
SA=a2+2aa24+h2−−−−−−√
cap s cap A is equal to A squared plus 2 A square root of the fraction with numerator A squared and denominator 4 plus h squared end root
SA=12ab+3(12lb)
cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren
SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√
cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root
SA=2(wl+lh+hw)
cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren
The correct formula for finding the surface area of a regular triangular pyramid is:
SA = lw + 1/2lw√(4h^2 + l^2) + 1/2lh√(4h^2 + w^2) + 1/2wh√(4h^2 + l^2)