A group of 29 campers is going on a field trip. Each car that goes on the trip can take 4 campers. Write an inequality that shows the minimum number of cars that will be sufficient to transport all the campers.
The camp parking lot has room for 10 cars. The camp counselors have already parked their 2 cars in the lot. Write an inequality to show the additional number of cars that can park in the lot.
Solve both inequalities. What number is a solution of both inequalities? If 29 campers need to be transported, and the cars need to gather in the camp parking lot before driving out, how many cars should be used for the trip?
Let x be the number of cars needed to transport all 29 campers.
1. Inequality for the minimum number of cars needed to transport all campers:
29 campers / 4 campers per car ≤ x
7.25 ≤ x
x ≥ 8 (since we cannot have a fraction of a car)
2. Inequality for the additional number of cars that can park in the lot:
Total number of cars - Counselors' cars ≤ 10
x - 2 ≤ 10
x ≤ 12
Solution for both inequalities: 8 ≤ x ≤ 12
Therefore, a minimum of 8 cars and a maximum of 12 cars should be used for the trip to transport all 29 campers and have enough room to park in the lot.