Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
To calculate the surface area of each book, we need to find the area of each of its 6 faces.
For Book A:
- Face 1: L * W = 6.5 * 1 = 6.5 square inches
- Face 2: L * H = 6.5 * 8.5 = 55.25 square inches
- Face 3: W * H = 1 * 8.5 = 8.5 square inches
- Face 4: L * H = 6.5 * 8.5 = 55.25 square inches
- Face 5: L * W = 6.5 * 1 = 6.5 square inches
- Face 6: W * H = 1 * 8.5 = 8.5 square inches
Total surface area for Book A: 6.5 + 55.25 + 8.5 + 55.25 + 6.5 + 8.5 = 140.5 square inches
For Book B:
- Face 1: L * W = 5.5 * 2 = 11 square inches
- Face 2: L * H = 5.5 * 8 = 44 square inches
- Face 3: W * H = 2 * 8 = 16 square inches
- Face 4: L * H = 5.5 * 8 = 44 square inches
- Face 5: L * W = 5.5 * 2 = 11 square inches
- Face 6: W * H = 2 * 8 = 16 square inches
Total surface area for Book B: 11 + 44 + 16 + 44 + 11 + 16 = 142 square inches
Therefore, Book A will require less wrapping paper based on surface area.