Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point) Responses Book A will require less wrapping paper because its surface area is 32.75 in.2 less than the surface area of Book B. Book A will require less wrapping paper because its surface area is 32.75 in.2 less than the surface area of Book B. Book B will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book A. Book B will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book A. Book A will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book B. Book A will require less wrapping paper because its surface area is 1.5 in.2 less than the surface area of Book B. Book B will require less wrapping paper because its surface area is 0.5 in.2 less than the surface area of Book A.

To find the surface area of a rectangular prism, you need to find the area of all six sides and then add them together.

For Book A:
- The front and back sides have dimensions 6.5 inches by 8.5 inches, so their areas are 6.5 inches * 8.5 inches = 55.25 square inches each.
- The top and bottom sides have dimensions 6.5 inches by 1 inch, so their areas are 6.5 inches * 1 inch = 6.5 square inches each.
- The left and right sides have dimensions 8.5 inches by 1 inch, so their areas are 8.5 inches * 1 inch = 8.5 square inches each.

Therefore, the total surface area of Book A is 2 * (55.25 square inches) + 2 * (6.5 square inches) + 2 * (8.5 square inches) = 221 square inches.

For Book B:
- The front and back sides have dimensions 5.5 inches by 8 inches, so their areas are 5.5 inches * 8 inches = 44 square inches each.
- The top and bottom sides have dimensions 5.5 inches by 2 inches, so their areas are 5.5 inches * 2 inches = 11 square inches each.
- The left and right sides have dimensions 8 inches by 2 inches, so their areas are 8 inches * 2 inches = 16 square inches each.

Therefore, the total surface area of Book B is 2 * (44 square inches) + 2 * (11 square inches) + 2 * (16 square inches) = 142 square inches.

Comparing the surface areas of Book A (221 square inches) and Book B (142 square inches), we can conclude that Book A will require less wrapping paper because its surface area is 79 square inches more than the surface area of Book B.

However, none of the given options match this calculation, so there seems to be an error in the provided responses.