Use the image to answer the question.

A coordinate plane of 4 quadrants shows x and y axes ranging from negative 3 to 3 in increments of 1. A line with arrows at each end intercepts two plotted points, A and B. Point A is plotted at left parenthesis 0 comma negative 1 right parenthesis. Point B is plotted at left parenthesis 1 comma 1 right parenthesis. The coordinates are not labeled.

Write the equation of the line in slope-intercept form.

(1 point)
y=___x+(___)

To find the slope of the line, we need to calculate the change in y divided by the change in x.

Slope = (1 - (-1)) / (1 - 0) = 2 / 1 = 2

Now that we have the slope, we can use point A (0, -1) to find the y-intercept by plugging in the values into the equation y = mx + b:

-1 = 2(0) + b
b = -1

Therefore, the equation of the line in slope-intercept form is:

y = 2x - 1

The answer is

y=2x+(-1)
ty

Apologies for the confusion. Both representations y = 2x - 1 and y = 2x + (-1) are correct and equivalent. Thank you for pointing that out.