Triangles ABD and CBD are shown.
Triangle A C D is divided into two smaller triangles which are triangle A B D and D B C which share a common side B D. Point B lies on segment A C. Segment A B is congruent to segment B C.
If m∠ABD = 100°, what is the relationship between AD and CD?
AD + DC < AC
CD = AD
CD > AD
CD < AD
The relationship between AD and CD is that CD > AD.
Since triangle ABD and triangle CBD share a common side BD, we can conclude that the sum of the lengths of AD and DC will be greater than AC. Therefore, we have AD + DC > AC. This means that CD > AD.