After you break apart a rectangular pyramid, what two-dimensional shapes appear in the net?(1 point)

Responses

triangles
triangles

square and triangle
square and triangle

rectangles
rectangles

rectangle and triangles

1. rectangle and triangles

2. the one that starts with 1/2
3. 522 ft.^2
4. the height from the apex straight down to the base of the triangular face where it forms a right angle

I forgot number 5. The answer is 170,000 mm^2

rectangle and triangles

nah im boutta violate you for that one, here is my respons for what you said: your the only mistake šŸ¤¦ā€ā™€ļøšŸ¤£šŸ±ā€šŸ’»

I apologize for any confusion or error in my previous response. If you have any more questions or need further clarification, feel free to ask. Thank you! šŸ™šŸ˜ŠšŸ¤–

Use the image to answer the question.

A rectangular pyramid is shown. The base of the pyramid has length labeled l and w. A dotted line is drawn from the apex down one of the triangular faces, ending at the midpoint of the edge that is labeled w. This dotted line is labeled slant height. From the apex down through the middle of the triangle is another dotted line labeled h.

What is the formula to solve for the slant height of the side triangles in the rectangular pyramid?

(1 point)
Responses

=lā‹…w
equals l times w

=(l2)2 + h2āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆš
equals Start Root left parenthesis Start Fraction l over 2 End Fraction right parenthesis squared plus h squared End Root

=(w2)2 +h2āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆš
equals Start Root left parenthesis Start Fraction w over 2 End Fraction right parenthesis squared plus h squared End Root

=h

Use the image to answer the question.

An illustration shows a pyramid with a square base. The side of the base is labeled 15 feet. The perpendicular height denoted by a right angle symbol on the lateral face from the apex to the base is labeled 9.9 feet.

Solve for the surface area of the square pyramid.

(1 point)
Responses

522 ft.2
522 ft. squared

299.25 ft.2
299.25 ft. squared

819 ft.2
819 ft. squared

148.5 ft.2

First, calculate the slant height of the pyramid using the Pythagorean theorem.

The slant height is the hypotenuse of a right triangle with legs 9.9 ft and 15 ft.

Slant height (s) = āˆš(9.9^2 + 15^2) = āˆš(98.01 + 225) = āˆš(323.01) = 17.97 ft (approximately)

The formula for the surface area of a square pyramid is:
Surface Area = Base Area + (1/2) * Perimeter of Base * Slant Height

Base Area = s^2 (since it's a square base)
Perimeter of Base = 4 * 15 (as it's a square)

Surface Area = 15^2 + (1/2) * 4 * 15 * 17.97
Surface Area = 225 + 30 * 17.97
Surface Area = 225 + 539.1
Surface Area = 764.1 ft^2

Therefore, the surface area of the square pyramid is approximately 764.1 ft^2.

None of the given options match the calculated value, so there seems to be a mistake in the provided options.

=(w^2/4+h^2)^0.5