Which of the following systems of equations has the solution (-2, 1)? This question requires you to show your work. (1 point) Responses 2x−y=−5 and x+2y=10 2 x minus y is equal to negative 5 and x plus 2 y is equal to 10 y=−32x−2 and 2x−y=−5 y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5 x−4y=8 and 3x+10=−2y x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y y=−2x−2 and 2x−2y=5
To find the solution to the system of equations, we substitute the given values (-2, 1) into each equation and see if they hold true.
1. For the system 2x-y=-5 and x+2y=10:
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5 (True)
(-2) + 2(1) = 10
-2 + 2 = 10
10 = 10 (True)
Therefore, the solution (-2, 1) satisfies the system of equations 2x-y=-5 and x+2y=10.