Which of the following systems of equations has the solution (-2, 1)? This question requires you to show your work. (1 point) Responses
x−4y=8 and 3x+10=−2y
y=−3/2x−2 and 2x−y=−5
2x−y=−5 and x+2y=10
y=−2x−2 and 2x−2y=5
show your work. NO MATRIX FORM
To find out if the solution (-2, 1) satisfies the system of equations, we substitute x=-2 and y=1 into each equation.
1) x−4y = 8
-2 - 4(1) = 8
-2 - 4 = 8
-6 = 8 [This equation is false]
2) 3x + 10 = −2y
3(-2) + 10 = -2(1)
-6 + 10 = -2
4 = -2 [This equation is false]
3) y = −3/2x − 2
1 = -3/2(-2) - 2
1 = 3 - 2
1 = 1 [This equation is true]
4) 2x - y = -5
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5 [This equation is true]
Therefore, the system of equations that has the solution (-2, 1) is:
2x - y = -5
y = −3/2x − 2