A spinner is divided into many sections of equalize. Some sections are red. Some are blue and the remaining are green. The probability of the arrow landed on a section colored red is 920. The probability of the arrow lining on a section colored blue is 620 what is the probability of the arrow landing on a green colored section?
Let P(R) be the probability of landing on a red section, P(B) be the probability of landing on a blue section, and P(G) be the probability of landing on a green section.
Therefore, we have:
P(R) = 9/20 = 0.45
P(B) = 6/20 = 0.30
Since the spinner is divided into red, blue, and green sections, the sum of their probabilities should equal 1.
Therefore,
P(R) + P(B) + P(G) = 1
0.45 + 0.30 + P(G) = 1
P(G) = 1 - 0.45 - 0.30
P(G) = 0.25
Therefore, the probability of the arrow landing on a green colored section is 0.25.