If the spinner is spun twice, what is the probability that the spinner will stop on a consonant and then again on a consonant?
The spinner is a circle divided into 6 equal sections. The sections are labeled L U Z O E and I.
A. two-ninths
B. one-third
C. one-sixth
D. one-ninth***
not sure tho cuz took PSAT all day in 7th grade so work was normal and didn't have time to do the lesson and there was sub so the teacher didn't move due date which is today
1/9 is correct
1/3 for 1st spin, 1/3 for 2nd spin. You just multiply them.
1/9 is correct!
yuppers! 1/9 is right
To find the probability of the spinner stopping on a consonant (L, Z, O) on the first spin and then stopping on a consonant on the second spin, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Step 1: Determine the favorable outcomes.
There are 3 consonants on the spinner: L, Z, O.
Given that we want a consonant followed by another consonant, we have 3 favorable outcomes.
Step 2: Determine the total number of possible outcomes.
The spinner has 6 equal sections.
Therefore, the total number of possible outcomes is 6.
Step 3: Calculate the probability.
The probability is given by the number of favorable outcomes divided by the total number of possible outcomes.
So, the probability is 3/6, which simplifies to 1/2.
Therefore, the correct answer is A. two-ninths