Find the perimeter of the rectangle with a vertices A(-8,3),b(-1,3),c(-1,-6),d(-8,-6)
To find the perimeter of the rectangle with vertices A(-8,3), B(-1,3), C(-1,-6), and D(-8,-6), we first need to find the lengths of each side of the rectangle.
We can calculate the length of the sides using the distance formula:
1. Length of side AB:
AB = √((X2-X1)² + (Y2-Y1)²)
AB = √((-1 - (-8))² + (3 - 3)²)
AB = √(7² + 0)
AB = √49
AB = 7 units
2. Length of side BC:
BC = √((X2-X1)² + (Y2-Y1)²)
BC = √((-1 - (-1))² + (-6 - 3)²)
BC = √(0² + (-9)²)
BC = √81
BC = 9 units
3. Length of side CD:
CD = √((X2-X1)² + (Y2-Y1)²)
CD = √((-8 - (-1))² + (-6 - (-6))²)
CD = √(-7² + 0)
CD = √49
CD = 7 units
4. Length of side DA:
DA = √((X2-X1)² + (Y2-Y1)²)
DA = √((-8 - (-8))² + (3 - (-6))²)
DA = √(0² + 9²)
DA = √81
DA = 9 units
Now, we can calculate the perimeter of the rectangle by adding the lengths of all sides together:
Perimeter = AB + BC + CD + DA
Perimeter = 7 + 9 + 7 + 9
Perimeter = 32 units
Therefore, the perimeter of the rectangle with vertices A(-8,3), B(-1,3), C(-1,-6), and D(-8,-6) is 32 units.