1) How many milliliters of the approximately 0.015 M copper(Il) sulfate solution are needed to prepare 100.00 milliliters of a 0.00030 M copper(Il) sulfate solution?
To find the volume of the first solution needed, we can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the first solution = 0.015 M
V1 = volume of the first solution (unknown)
C2 = concentration of the second solution = 0.00030 M
V2 = volume of the second solution = 100.00 mL
Plugging in the values:
(0.015 M)(V1) = (0.00030 M)(100.00 mL)
Solving for V1:
V1 = (0.00030 M)(100.00 mL) / 0.015 M
V1 = 2.00 mL
Therefore, approximately 2.00 milliliters of the 0.015 M copper(II) sulfate solution are needed to prepare 100.00 milliliters of a 0.00030 M copper(II) sulfate solution.