Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.

Question

Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.

In three to five sentences, explain how you can find the mass of the ammonia. Then, given , R=(0.0821L * atm)/(mol* k) calculate the mass.

PV=nRT n 1 mole= 17 grams…….multiply the number of moles by 17

Answer 1

To find the mass of the ammonia gas, we first need to calculate the number of moles present in the sample. Using the ideal gas law equation PV = nRT, we can solve for n (number of moles) by rearranging the equation to n = PV / RT. Given that P = 1.2 atm, V = 3.7 L, R = 0.0821 L * atm / (mol * K), and T = 290K, we can plug in these values to find the number of moles. Once we have the number of moles, we can multiply it by the molar mass of ammonia (17 grams/mol) to find the mass of the sample. In this case, the mass of the ammonia gas sample would be equal to n (number of moles) multiplied by the molar mass of 17 grams/mol.