Ammonia gas has a molar mass of approximately 17 grams per mole. At 290K and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
In three to five sentences, explain how you can find the mass of the ammonia. Then, given R=0.0821L⋅atmmol⋅K, calculate the mass.
To find the mass of the ammonia gas, you can first calculate the number of moles of ammonia using the ideal gas law equation: PV = nRT. Rearrange the equation to solve for n (number of moles): n = PV / RT. Then, multiply the number of moles by the molar mass of ammonia to obtain the mass. With the given values, the number of moles of ammonia can be calculated as: n = (1.2 atm * 3.7 L) / (0.0821 L⋅atmmol⋅K * 290K) = 0.176 moles. Finally, multiply the number of moles by the molar mass (17 grams/mole) to find the mass: 0.176 moles * 17 grams/mole = 2.992 grams.
To find the mass of the ammonia gas, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. The equation can be rearranged to solve for the number of moles (n), which is equal to PV/RT. Once we have the number of moles, we can multiply it by the molar mass of ammonia to calculate the mass.
Given P = 1.2 atm, V = 3.7 L, R = 0.0821 L·atm/mol·K, and T = 290 K, we can now calculate the number of moles. Substituting these values into the equation, we get n = (1.2 atm * 3.7 L) / (0.0821 L·atm/mol·K * 290 K) = 0.182 mol.
Since the molar mass of ammonia is approximately 17 g/mol, we can now calculate the mass by multiplying the number of moles by the molar mass. Thus, the mass of the ammonia is 0.182 mol * 17 g/mol = 3.094 grams.
To find the mass of ammonia, you can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation to solve for n, we have n = PV / RT.
First, convert the pressure from atm to Pa by multiplying it by 101325 (1 atm = 101325 Pa). Then, convert the volume from liters to m^3 by multiplying it by 0.001 (1 L = 0.001 m^3).
So, n = (1.2 atm * 101325 Pa/atm) * (3.7 L * 0.001 m^3/L) / (0.0821 L.atm/mol.K * 290 K).
Next, calculate the mass by multiplying the number of moles (n) by the molar mass of ammonia (17 g/mol). Finally, plug in the values to get the mass: mass = n * molar mass = (1.2 atm * 101325 Pa/atm) * (3.7 L * 0.001 m^3/L) / (0.0821 L.atm/mol.K * 290 K) * 17 g/mol.
Calculating this expression gives us the mass of the ammonia gas at those conditions.