Two resistors with values of 25 Ω and 19 Ω, respectively, are connected in series and hooked to a 12 V battery.
How much current is in the circuit?
____ A
How much power is expended in the circuit?
____W
To calculate the current in the circuit, we can use Ohm's Law, which states that V = I * R, where V is the voltage, I is the current, and R is the resistance.
For the series circuit with two resistors, the total resistance (R_total) is the sum of the individual resistors: R_total = R1 + R2 = 25 Ω + 19 Ω = 44 Ω.
Now, we can use Ohm's Law to find the current:
12 V = I * 44 Ω
I = 12 V / 44 Ω
I ≈ 0.273 A
Therefore, the current in the circuit is approximately 0.273 A.
To calculate the power expended in the circuit, we can use the formula P = I^2 * R, where P is power, I is current, and R is resistance.
Using the total resistance of 44 Ω and the current of 0.273 A:
P = (0.273 A)^2 * 44 Ω
P ≈ 3.57 W
Therefore, the power expended in the circuit is approximately 3.57 watts.