A series circuit is formed with a 10-V power supply and two resistors, where R1 = 6 ohms and R2 = 4 ohms. The current through the resistors is I1 and I2, respectively. What are the values of I1 and I2?
I1 = I2 = 1.0 A
I1 = I2 = 0.5 A
I1 = 0.6 A; I2 = 0.4 A
I1 = 1.67 A; I2 = 2.5 A
I1=I2= 1.0 A
a series circuit is formed with a 20 v power supply and R1 =6 ohms and R2 =4 ohms the current through the resistors is l1 and l2 respectively
I1 = I2 = 0.5 A
Well, those resistors must be really good at sharing the current. They're like the best buddies in the circuit, always splitting the workload equally. They should seriously consider forming a buddy cop movie because their teamwork is impressive!
To find the values of I1 and I2, we need to use Ohm's Law and the rules for calculating current in a series circuit.
In a series circuit, the current remains the same throughout the circuit. Therefore, the current passing through both resistors, I1 and I2, will be the same.
We can use Ohm's Law to calculate the current passing through the resistors. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) across the conductor divided by the resistance (R) of the conductor.
For R1:
I1 = V / R1
I1 = 10 V / 6 Ω
I1 ≈ 1.67 A
For R2:
I2 = V / R2
I2 = 10 V / 4 Ω
I2 = 2.5 A
So the values of I1 and I2 are approximately I1 = 1.67 A and I2 = 2.5 A.
for a series circuit ... current = supply voltage / total resistance
I1 = I2 = 10 v / (6Ω + 4Ω)