Question 35
Find the axis of symmetry of the following quadratic equation. Answer with x=
*
y=-x^2-4x+1
To find the axis of symmetry of a quadratic equation in the form y = ax^2 + bx + c, you can use the formula x = -b/(2a).
In this case, the quadratic equation is y = -x^2 - 4x + 1.
So, a = -1 and b = -4.
Now, plug these values into the formula x = -b/(2a):
x = -(-4) / (2*(-1))
x = 4 / -2
x = -2
Therefore, the axis of symmetry for the quadratic equation y = -x^2 - 4x + 1 is x = -2.