Question 35
Find the axis of symmetry of the following quadratic equation. Answer with x=
y = -x^2 - 4x + 1
To find the axis of symmetry of a quadratic equation in the form of y = ax^2 + bx + c, you can use the formula x = -b / 2a.
In the given equation y = -x^2 - 4x + 1, a = -1 and b = -4.
axis of symmetry: x = -(-4) / 2(-1)
axis of symmetry: x = 4 / -2
axis of symmetry: x = -2
Therefore, the axis of symmetry of the quadratic equation y = -x^2 - 4x + 1 is x = -2.