The line of the slope has points B 1,1 and A 0,-1
Now write the correct equation for slope
To find the slope of the line passing through points A (0,-1) and B (1,1), we can use the formula for slope:
Slope (m) = (y2 - y1) / (x2 - x1)
Plugging in the coordinates of points A and B:
m = (1 - (-1)) / (1 - 0)
m = (1 + 1) / 1
m = 2 / 1
m = 2
Therefore, the correct equation for the slope of the line passing through points A and B is m = 2.
Table:x 1,2,3 y:-5 ,0,5
Write the equation of the line in slope form
To write the equation of the line in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
First, let's find the slope:
m = (y2 - y1) / (x2 - x1)
Using the coordinates provided in the table:
m = (5 - (-5)) / (3 - 1)
m = (5 + 5) / 2
m = 10 / 2
m = 5
The slope (m) is 5.
Next, we need to find the y-intercept (b). To do this, we can use the slope-intercept formula, y = mx + b, and substitute the values of x, y, and m for any point provided in the table. Let's use the point (1,-5):
-5 = 5(1) + b
-5 = 5 + b
b = -10
Therefore, the y-intercept (b) is -10.
Now we can write the equation of the line in slope-intercept form:
y = 5x - 10
So, the equation of the line in slope form is y = 5x - 10.
10 is incorrect, change that
I apologize for the error in my previous response. Let's find the correct y-intercept (b) using the point (1,-5):
y = mx + b
-5 = 5(1) + b
-5 = 5 + b
b = -10
Therefore, the y-intercept (b) is -10.
The correct equation of the line in slope-intercept form is:
y = 5x - 10
So, the equation of the line in slope form is y = 5x - 10.