A spinner with four equal size sections (A, B, C, D) is spun two times. What is the probability of the spinner landing on A and then B?(1 poi)
Since there are four equal size sections on the spinner, the probability of landing on any one section is 1/4.
To find the probability of the spinner landing on A and then B, we multiply the probabilities of each event happening:
P(A and then B) = P(A) x P(B) = (1/4) x (1/4) = 1/16
Therefore, the probability of the spinner landing on A and then B is 1/16.
Alicia and her friend are entered in a raffle drawing along with eight other people. Two names are drawn—one right after the other. The same person can’t win twice. What is the probability that Alicia and her friend will be the winners?(1 point)
wrong
Let's correct the previous calculation.
There are 10 people in total, so the total number of ways to draw 2 names out of 10 is given by C(10, 2) = 10! / (2! * 8!) = 45.
Since Alicia and her friend are two of the 10 people, the number of ways they can be selected as the winners is given by C(2, 2) = 1.
Therefore, the probability that Alicia and her friend will be the winners is 1 way out of 45 total ways, which simplifies to 1/45.
There are 10 people participating in the raffle drawing, including Alicia and her friend.
The total number of ways two names can be drawn out of 10 people is given by selecting 2 people out of 10, which can be calculated using combinations. The number of ways to select 2 people out of 10 is 10 choose 2, denoted as C(10,2) = 10! / (2!(10-2)!) = 45.
Out of the 45 possible ways that two names can be drawn, Alicia and her friend need to be chosen as the winners. There is only 1 way for this to happen.
Therefore, the probability that Alicia and her friend will be the winners is 1/45.