A jar contains jelly beans. There are
5
5 red jelly beans,
3
3 blue jelly beans and
3
3 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify.
The total number of jelly beans is 5 + 3 + 3 = 11.
The probability of choosing a red jelly bean first is 5/11.
After choosing a red jelly bean, there are only 10 jelly beans left, with 3 green jelly beans. Therefore, the probability of choosing a green jelly bean second is 3/10.
Therefore, the probability of choosing one red jelly bean and one green jelly bean is (5/11) * (3/10) = 15/110 = 3/22.