A jar contains jelly beans. There are
9
9 red jelly beans,
8
8 blue jelly beans and
8
8 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that both are blue? Write your answer as a fraction. You do not need to simplify.
The total number of jelly beans in the jar is 9 + 8 + 8 = 25.
The probability of picking a blue jelly bean on the first draw is 8/25.
After picking a blue jelly bean on the first draw, there are then 24 jelly beans left in the jar, with 7 blue jelly beans remaining.
So, the probability of picking a blue jelly bean on the second draw is 7/24.
Multiplying these probabilities together:
(8/25) * (7/24) = 56/600 = 14/150
Therefore, the probability that both jelly beans are blue is 14/150.
A jar contains jelly beans. There are
5
5 red jelly beans,
6
6 blue jelly beans and
3
3 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify.
The total number of jelly beans in the jar is 5 + 6 + 3 = 14.
The probability of picking a red jelly bean on the first draw is 5/14.
After picking a red jelly bean on the first draw, there are then 13 jelly beans left in the jar, with 3 green jelly beans remaining.
So, the probability of picking a green jelly bean on the second draw is 3/13.
However, there is also the possibility of picking a green jelly bean on the first draw and then a red jelly bean on the second draw.
The probability of picking a green jelly bean on the first draw is 3/14.
After picking a green jelly bean on the first draw, there are then 13 jelly beans left in the jar, with 5 red jelly beans remaining.
So, the probability of picking a red jelly bean on the second draw is 5/13.
Adding these two possibilities together:
(5/14) * (3/13) + (3/14) * (5/13) = 15/182 + 15/182 = 30/182
Therefore, the probability that one jelly bean is red and the other jelly bean is green is 30/182.
The baseball store has 5 types of gloves and 2 cleats. Assuming you will pick exactly one of each how many different possibilities are there?
To find the number of different possibilities when picking one glove and one cleat, we can simply multiply the number of options for each item.
Number of options for gloves = 5
Number of options for cleats = 2
Total number of possibilities = 5 (types of gloves) * 2 (types of cleats) = 10
Therefore, there are 10 different possibilities when picking one of each item from the baseball store.
The baseball store has 5 different types of bats, 5 types of gloves and 2 types of cleats. Assuming you will pick exactly one of each how many different possibilities are there?
To find the total number of different possibilities when picking one of each item (a bat, a glove, and a cleat), we need to multiply the number of options for each item.
Number of options for bats = 5
Number of options for gloves = 5
Number of options for cleats = 2
Total number of possibilities = 5 (types of bats) * 5 (types of gloves) * 2 (types of cleats) = 50
Therefore, there are 50 different possibilities when picking exactly one of each item from the baseball store.
A fast food offers a special for $9.99. The customer can choose from 3 types of main courses,4 types of sides, 6 drinks, and 2 sauces. Assuming you will pick exactly one of each how many different possibilities are there?
To find the total number of different possibilities when picking one of each item (a main course, a side, a drink, and a sauce), we need to multiply the number of options for each category.
Number of options for main courses = 3
Number of options for sides = 4
Number of options for drinks = 6
Number of options for sauces = 2
Total number of possibilities = 3 (types of main courses) * 4 (types of sides) * 6 (types of drinks) * 2 (types of sauces) = 144
Therefore, there are 144 different possibilities when picking exactly one of each item from the fast food offer.