A jar contains jelly beans. There are
3
3 red jelly beans,
6
6 blue jelly beans and
3
3 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify. Click Here for Help Video
To find the probability of picking one red jelly bean and one green jelly bean, we first need to find the total number of ways we can pick two jelly beans out of the jar.
There are a total of 3 red jelly beans, 6 blue jelly beans, and 3 green jelly beans, so there are 12 jelly beans in total.
The total number of ways to pick two jelly beans out of 12 is given by the combination formula:
C(12, 2) = 12! / (2!(12-2)!) = 66
Next, we need to find the number of ways to pick one red jelly bean and one green jelly bean.
There are 3 ways to pick one red jelly bean and 3 ways to pick one green jelly bean, for a total of 3 * 3 = 9 ways.
Therefore, the probability of picking one red jelly bean and one green jelly bean is:
9 / 66 = 3 / 22
So the probability is 3/22.
A jar contains jelly beans. There are
3
3 red jelly beans,
6
6 blue jelly beans and
3
3 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify. Click Here for Help Video
To calculate the probability that one jelly bean is red and the other jelly bean is green, we need to find the total number of ways to choose 2 jelly beans out of the total number of jelly beans in the jar.
There are a total of 12 jelly beans in the jar (3 red + 6 blue + 3 green).
The total number of ways to choose 2 jelly beans out of 12 is given by the combination formula:
C(12, 2) = 12! / (2!(12-2)!) = 66
Next, we need to calculate the number of ways to choose one red jelly bean and one green jelly bean. Since there are 3 red jelly beans and 3 green jelly beans, there are 3*3=9 ways to choose one red and one green.
Therefore, the probability that one jelly bean is red and the other jelly bean is green is:
9 / 66 = 9/66
Therefore, the probability is 9/66.
1.
A jar contains jelly beans. There are
3
3 red jelly beans,
6
6 blue jelly beans and
3
3 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify. Click Here for Help Video
2.
A jar contains jelly beans. There are
9
9 red jelly beans,
6
6 blue jelly beans and
10
10 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that both are blue? Write your answer as a fraction. You do not need to simplify. Click Here for Help Video
3.
the baseball store has
7
7 different types of bats,
5
5 types of gloves and
2
2 types of cleats. Assuming you will pick exactly one of each how many different possibilities are there?
1. For the first question, where the jar contains 3 red jelly beans, 6 blue jelly beans, and 3 green jelly beans, and you randomly take two jelly beans out to eat, the probability that one jelly bean is red and the other jelly bean is green can be found as follows:
Total number of ways to pick 2 jelly beans from 12 jelly beans = C(12, 2) = 12! / (2!(12-2)!) = 66
Number of ways to pick 1 red jelly bean and 1 green jelly bean = 3 * 3 = 9
Probability = 9 / 66 = 9/66
Therefore, the probability is 9/66.
2. For the second question, where the jar contains 9 red jelly beans, 6 blue jelly beans, and 10 green jelly beans, and you randomly take two jelly beans out to eat, the probability that both are blue can be found as follows:
Total number of ways to pick 2 jelly beans from 25 jelly beans = C(25, 2) = 25! / (2!(25-2)!) = 300
Number of ways to pick 2 blue jelly beans = C(6, 2) = 6! / (2!(6-2)!) = 15
Probability = 15 / 300 = 15/300
Therefore, the probability is 15/300.
3. For the third question, where the baseball store has 7 different types of bats, 5 types of gloves, and 2 types of cleats, and you will pick exactly one of each, the total number of different possibilities can be calculated by multiplying the number of options for each item:
Total number of possibilities = 7 * 5 * 2 = 70
Therefore, there are 70 different possibilities.
4.
A fast food offers a special for $9.99. The customer can choose from
3
3 types of main courses,
4
4 types of sides,
5
5 drinks, and
3
3 sauces. Assuming you will pick exactly one of each how many different possibilities are there?
5.
The sub shop has
7
7 different kinds of bread,
4
4 types of cheese,
4
4 types of meat,
4
4 vegetable toppings and
9
9 types of sauce. Assuming you will pick exactly one of each how many different possibilities are there?
6.
Find the volume of the cylinder below. Click Here for Help Video
36
36 feet
38
38 feet
The volume is
ft³.
4. For the fast-food special offer where the customer can choose from 3 types of main courses, 4 types of sides, 5 drinks, and 3 sauces, and you will pick exactly one of each, the total number of different possibilities can be calculated by multiplying the number of options for each item:
Total number of possibilities = 3 * 4 * 5 * 3 = 180
Therefore, there are 180 different possibilities.
5. For the sub shop which has 7 different kinds of bread, 4 types of cheese, 4 types of meat, 4 vegetable toppings, and 9 types of sauce, and you will pick exactly one of each, the total number of different possibilities can be calculated by multiplying the number of options for each item:
Total number of possibilities = 7 * 4 * 4 * 4 * 9 = 1008
Therefore, there are 1008 different possibilities.
6. To find the volume of the cylinder provided with dimensions:
Radius = 36 feet
Height = 38 feet
The formula for the volume of a cylinder is V = πr^2h, where r is the radius and h is the height.
Plugging in the values:
V = π * 36^2 * 38
V = 40992π ft³
Therefore, the volume of the cylinder is 40992π ft³.