Find any points of discontinuity for the rational function. y = (x-8)/(x^2 + 5x - 6)
To find the points of discontinuity for the given rational function y = (x-8)/(x^2 + 5x - 6), we need to determine where the denominator of the function is equal to zero.
Factoring the denominator:
x^2 + 5x - 6 = (x + 6)(x - 1)
Setting the denominator equal to zero:
(x + 6)(x - 1) = 0
x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Therefore, the points of discontinuity for the rational function occur at x = -6 and x = 1. These are the values of x where the function is undefined because the denominator is zero.