The pedigree below tracks the presence of dimples through a family's generation. Having dimples is an autosomal dominant trait. If individual III-3 married a woman who was heterozygous for dimples what is the percent chance their children will have dimples? 0%, 25%, 75%, 100%,

50%

Individual III-3 has the genotype Dd (heterozygous for dimples). If his wife is also heterozygous for dimples, then she would also have the genotype Dd.

Therefore, the Punnett square for their potential offspring would be:

D d
D DD Dd
d Dd dd

So, 50% of their children would have dimples (genotype DD or Dd) and 50% would not have dimples (genotype dd).

their is No answer or choice for 50 %

In that case, the closest answer choice would be 75%. This is because 3 out of the 4 squares in the Punnett square show offspring with dimples (genotype DD or Dd), which is equivalent to 75%.