Given that (20,x,29)
is a Pythagorean triple and x is less than 29
, what is the value of x?(1 point)
To find the value of x in the Pythagorean triple (20, x, 29), we can use the Pythagorean theorem:
a^2 + b^2 = c^2
where a and b are the two shorter sides of the right triangle and c is the hypotenuse.
In this case, a = 20, b = x, and c = 29. Substituting these values into the Pythagorean theorem, we get:
20^2 + x^2 = 29^2
400 + x^2 = 841
x^2 = 841 - 400
x^2 = 441
Taking the square root of both sides, we get:
x = √441
x = 21
So, the value of x in the Pythagorean triple (20, x, 29) is 21.