What value of x that is less than 51 will make (x, 45,51) a Pythagorean triple?
To check if the triplet (x, 45, 51) is a Pythagorean triple, we can use the Pythagorean theorem:
x^2 + 45^2 = 51^2
Simplifying, we have:
x^2 + 2025 = 2601
Subtracting 2025 from both sides:
x^2 = 576
Taking the square root of both sides:
x = ±24
Since we are looking for a value of x that is less than 51, the only solution that satisfies this condition is x = -24. Thus, -24 is the value of x that makes (x, 45, 51) a Pythagorean triple.