Which of the following systems of equations has the solution (-2, 1)? This question requires you to show your work. (1 point)
Responses x−4y=8 and 3x+10=−2y x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y y=−32x−2 and 2x−y=−5 y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5 2x−y=−5 and x+2y=10 2 x minus y is equal to negative 5 and x plus 2 y is equal to 10 y=−2x−2 and 2x−2y=5
show your work . Do not use matrix form.
Let's plug in the values x = -2 and y = 1 into each of the systems of equations:
1. x−4y=8
-2 - 4(1) = 8
-2 - 4 = 8
-6 = 8 ❌
2. 3x+10=−2y
3(-2) + 10 = -2(1)
-6 + 10 = -2
4 = -2 ❌
3. y=−3/2x−2
1 = -3/2(-2) - 2
1 = 3 - 2
1 = 1 ✅
4. 2x−y=−5
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5 ✅
5. 2x-y=-5
2(-2) - 1 = -5
-4 - 1 = -5
-5 = -5 ✅
6. x+2y=10
-2 + 2(1) = 10
-2 + 2 = 10
0 = 10 ❌
Based on the calculations, the system of equations with the solution (-2, 1) is:
3. y=-3/2x−2
4. 2x−y=−5
5. 2x−y=−5