One of the games at a carnival involves trying to ring a bell with a ball by hitting a lever that propels the ball into the air. The height of the ball is modeled by the equation
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If the bell is 25 ft above ground will it be hit by the ball?
One of the games at a carnival involves trying to ring a bell with a ball by hitting a lever that propels the ball into the air. The height of the ball is modeled by the equation
h(t)=-16t^2+39t
If the bell is 25 ft above ground will it be hit by the ball? yes, no, not enough info
To determine if the bell will be hit by the ball, we need to find the time at which the height of the ball is equal to 25 ft.
So, we need to solve the equation:
-16t^2 + 39t = 25
Rearranging the equation, we get:
-16t^2 + 39t - 25 = 0
We can use the quadratic formula to solve for t:
t = (-39 ± √(39^2 - 4(-16)(-25))) / 2(-16)
Calculating the values, we get t ≈ 0.44 and t ≈ 1.56.
Therefore, the height of the ball reaches 25 ft at around t = 0.44 and t = 1.56 seconds. This means that the ball will pass the bell twice during its flight.
Therefore, the bell will be hit by the ball.