Our middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played?(1 point) Responses 0.25x 3≤10 ; 28 games 0 point 2 5 x plus 3 is less than or equal to 10; 28 games 0.25x−3≤10 ; 52 games 0 point 2 5 x minus 3 is less than or equal to 10; 52 games 0.25x−3<10 ; 52 games 0.25x−3<10 ; 52 games 0.25x 3<10 ; 28 games 0.25x 3<10 ; 28 games
admission for entry 3 bucks that takes 3 away from ten so you have 7 bucks, with the 7 bucks you got you can play 28 games
The correct inequality that represents the possible number of games that can be played with $10 is 0.25x + 3 ≤ 10, where x represents the number of games. To find the maximum number of games, we need to solve the inequality:
0.25x + 3 ≤ 10
Subtracting 3 from both sides:
0.25x ≤ 7
Dividing both sides by 0.25:
x ≤ 28
Therefore, the maximum number of games that can be played with $10 is 28 games.