Your middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played?
Responses
A 0.25x + 3 < 10; 28 games0.25x + 3 < 10; 28 games
B 0.25x + 3 ≤ 10; 28 games0.25x + 3 ≤ 10; 28 games
C 0.25x - 3 < 10; 52 games0.25x - 3 < 10; 52 games
D 0.25x - 3 ≤ 10; 52 games
B 0.25x + 3 ≤ 10; 28 games
To find the maximum number of games that can be played with $10, we need to set up an inequality where the total cost of admission and games played is less than or equal to $10.
Let x represent the number of games played.
Therefore, the inequality is: 0.25x + 3 ≤ 10
Solving for x, we get: 0.25x ≤ 7; x ≤ 28
Thus, the maximum number of games that can be played with $10 is 28 games.