Calculate P(A or B)
in the following scenarios:
a. P(A)=0.34,P(B)=0.34
; A
and B
are mutually exclusive
P(A or B)=
0.34
Round to two decimal places
b. P(A)=0.18,P(B)=0.22,P(A and B)=0.07
P(A or B)=
Round to two decimal places
c. P(A)=0.67,P(B)=0.63,P(A and B)=0.57
P(A or B)=
Round to two decimal places
d. P(A)=0.4,P(B)=0.6
; A
and B
are independent
P(A or B)=
Round to two decimal places
a. P(A or B) = P(A) + P(B) = 0.34 + 0.34 = 0.68
b. P(A or B) = P(A) + P(B) - P(A and B) = 0.18 + 0.22 - 0.07 = 0.33
c. P(A or B) = P(A) + P(B) - P(A and B) = 0.67 + 0.63 - 0.57 = 0.73
d. Since A and B are independent, P(A and B) = P(A) * P(B) = 0.4 * 0.6 = 0.24
Therefore, P(A or B) = P(A) + P(B) - P(A and B) = 0.4 + 0.6 - 0.24 = 0.76