If P(G) = 0.2, P(H) = 0.3, and G and H are mutually exclusive, find P(G and H).
Given that G and H are mutually exclusive events, this means that they cannot occur at the same time. Therefore, P(G and H) = 0.
To find P(G and H), we need to use the formula for the probability of the intersection of two mutually exclusive events.
When two events are mutually exclusive, it means that they cannot happen at the same time. In this case, G and H are mutually exclusive.
The formula for the probability of the intersection of two mutually exclusive events is:
P(G and H) = 0
Since G and H are mutually exclusive, their intersection cannot occur, so the probability of both G and H happening at the same time is zero (0).
To find P(G and H), you need to determine the probability of both events G and H occurring at the same time. However, because G and H are mutually exclusive, it means that they cannot both occur simultaneously. In other words, if G happens, then H cannot happen, and vice versa.
Since G and H cannot occur together, the probability of them both happening at the same time is zero. Therefore, P(G and H) = 0.