Solve the system by the substitution method.
5x+7y=-18
y=5x-14
5x+7(5x-14)=-18
5x+35x-98=-18
40x=80
you take it from there.
To solve the system of equations using the substitution method, we'll substitute the value of y from the second equation into the first equation.
Given:
Equation 1: 5x + 7y = -18
Equation 2: y = 5x - 14
Substitute y = 5x - 14 into Equation 1:
5x + 7(5x - 14) = -18
Simplify the equation:
5x + 35x - 98 = -18
40x - 98 = -18
Add 98 to both sides of the equation to isolate 40x:
40x - 98 + 98 = -18 + 98
40x = 80
Divide both sides of the equation by 40 to solve for x:
(40x)/40 = 80/40
x = 2
Now substitute the value of x back into Equation 2 to solve for y:
y = 5(2) - 14
y = 10 - 14
y = -4
Therefore, the solution to the system of equations is x = 2 and y = -4.
To solve the system of equations using the substitution method, we will substitute the value of "y" from the second equation into the first equation.
Given system of equations:
1) 5x + 7y = -18
2) y = 5x - 14
Step 1: Start by substituting the value of "y" from equation 2) into equation 1).
5x + 7(5x - 14) = -18
Step 2: Simplify the equation by distributing the 7 on the second term.
5x + 35x - 98 = -18
Step 3: Combine like terms.
40x - 98 = -18
Step 4: Add 98 to both sides of the equation to isolate the x-term.
40x = 80
Step 5: Divide both sides by 40 to solve for x.
x = 2
Step 6: Substitute the value of x = 2 into the second equation to find the value of y.
y = 5(2) - 14
y = 10 - 14
y = -4
Therefore, the solution to the system of equations is x = 2 and y = -4.