A side of the triangle below has been extended to form an exterior angle of 124°. Find the value of xx. 124° x°
The sum of the exterior angles of a triangle is always 360°.
Since one of the exterior angles is 124°, the sum of the other two exterior angles must be 360° - 124° = 236°.
Let's denote the other two exterior angles as a and b.
a + b = 236°
Since a and b are the exterior angles of the triangle, they are supplementary to their corresponding interior angles.
So, a = x, and b = x.
x + x = 236°
2x = 236°
x = 236° / 2
x = 118°
Therefore, the value of x is 118°.