A side of the triangle below has been extended to form an exterior angle of 124°. Find the value of xx.
Since the exterior angle of a triangle is equal to the sum of the two opposite interior angles, we know that $x+60 = 124$. Solving for $x$ gives us $x = \boxed{64}$. [asy]
pair A,B,C,D;
A=(0,0);
B=(50,0);
C=(15,25);
D=(-18,-30);
draw(D--B--C--D);
draw(C--A);
label("$A$",A,S);
label("$B$",B,S);
label("$C$",C,N);
label("$D$",D,S);
label("$60^\circ$",(23,22),S);
label("$124^\circ$",(5,-8),S);
label("$x^\circ$",(43,-10),S);
[/asy]