There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.
The net of a rectangular prism is shown. What is the surface area of the rectangular prism?
(1 point)
Responses
138 cm.2
138 cm.2
306 cm.2
306 cm.2
104 cm.2
104 cm.2
208 cm.2
The surface area of a rectangular prism can be calculated by adding together the areas of each of its six faces.
In this case, we have:
- The front face: 7cm * 2cm = 14cm^2
- The back face: 10cm * 2cm = 20cm^2
- The top face: 7cm * 10cm = 70cm^2
- The bottom face: 7cm * 10cm = 70cm^2
- The left side face: 2cm * 10cm = 20cm^2
- The right side face: 2cm * 10cm = 20cm^2
Adding these together, we get:
14cm^2 + 20cm^2 + 70cm^2 + 70cm^2 + 20cm^2 + 20cm^2 = 214cm^2
Therefore, the surface area of the rectangular prism is 214 cm^2.
None of the provided answer choices match this calculation.