In a 6 hour festival of short films the number of films (f) that can be presented so each film will have at least 1/3 of an hour to be shown can be expressed as 6/f >2/3 what is the solution of this inequality
To solve the inequality 6/f > 2/3, we can first simplify the right side of the inequality:
2/3 = 4/6
Now we have:
6/f > 4/6
Multiply both sides by f to get rid of the fraction:
6 > 4f/6
Multiply both sides by 6:
36 > 4f
Divide by 4:
f < 9
Therefore, the solution to the inequality 6/f > 2/3 is f < 9. This means that the festival can present up to 8 short films to ensure each film has at least 1/3 of an hour to be shown.