Use the image to answer the question.
There are four adjoining rectangles of the same height positioned so their vertical sides touch. The first and third rectangles from the left are the same size as each other. The second and fourth rectangles from the left are also the same size as each other but wider than the first and third. The first rectangle is labeled 7 centimeters on the left side and 2 centimeters on the bottom side. The fourth rectangle is labeled 10 centimeters on the bottom side. The second rectangle has identical small rectangles touching its top and bottom sides. The small rectangles are the same width as the second rectangle.
The net of a rectangular prism is shown. What is the surface area of the rectangular prism?
(1 point)
Responses
138 cm.2
138 cm.2
306 cm.2
306 cm.2
104 cm.2
104 cm.2
208 cm.2
The surface area of the rectangular prism can be calculated by finding the area of each face and adding them together.
The area of the first face is 7 cm x 2 cm = 14 cm^2.
The area of the second face is 7 cm x 10 cm = 70 cm^2.
The area of the third face is 7 cm x 2 cm = 14 cm^2.
The area of the fourth face is 10 cm x 10 cm = 100 cm^2.
The area of the fifth face is 10 cm x 2 cm = 20 cm^2.
The area of the sixth face is 10 cm x 2 cm = 20 cm^2.
Adding all the areas together, we get:
14 cm^2 + 70 cm^2 + 14 cm^2 + 100 cm^2 + 20 cm^2 + 20 cm^2 = 238 cm^2.
Therefore, the surface area of the rectangular prism is 238 cm^2.
So the closest option to that answer would be 238 cm^2.