A gymnasium is 45 ft long, 30 ft wide, and 14 ft high (tall). The school is painting the walls and the ceiling of the gym. Find the area of the painted parts of the gym.
HINT READ ME: The floor is NOT painted. The formula for SA is PH+2B (the 2B part included the floor and ceiling, if you are not painting the floor then you would only use 1 B and not multiply by 2) Formula you would use is: S=PH+B
To find the area of the painted parts of the gym, we need to calculate the surface area of the walls and ceiling.
First, let's calculate the surface area of the walls. The gym has four walls, each with dimensions of 45 ft (length) by 14 ft (height). So, the total surface area of the walls is:
2(45 ft x 14 ft) + 2(30 ft x 14 ft)
= 2(630 ft^2) + 2(420 ft^2)
= 1260 ft^2 + 840 ft^2
= 2100 ft^2
Next, let's calculate the surface area of the ceiling. The ceiling has a dimension of 45 ft (length) by 30 ft (width). So, the surface area of the ceiling is:
45 ft x 30 ft = 1350 ft^2
Therefore, the total area of the painted parts of the gym is:
2100 ft^2 (walls) + 1350 ft^2 (ceiling) = 3450 ft^2
So, the area of the painted parts of the gym is 3450 square feet.