Solve the system of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30
First, multiply the second equation by 2 to get rid of the coefficients in front of x:
-2x + 4y = 30 becomes -4x + 8y = 60
Now we have the system of equations:
4x - 6y = -48
-4x + 8y = 60
Now add the two equations together:
(4x - 6y) + (-4x + 8y) = -48 + 60
-6y + 8y = 12
2y = 12
y = 6
Now substitute y = 6 into one of the original equations to solve for x. Using the first equation:
4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3
So the solution to the system of equations is x = -3, y = 6.