A sample of oxygen gas has a volume of 2.5 L at a pressure of 4.0 atm. The temperature and the number of gas particles do not change.
Part 1 of 2
What is the volume of gas (in L) at 28.0 atm? Be sure your answer has the correct number of significant figures.
L
V2 = (P1/P2) * V1
V2 = (4.0 atm / 28.0 atm) * 2.5 L
V2 = 0.142857 * 2.5 L
V2 = 0.357 L
Therefore, the volume of gas at 28.0 atm is 0.357 L.