A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill? KE=12mv2 (1 point) Responses 592,416 J 592,416 J 1,184,832 J 1,184,832 J 2,978,944 J 2,978,944 J 17,952 J
To calculate the kinetic energy of the car at the bottom of the hill, we can use the formula:
KE = 1/2 * m * v^2
Where:
KE = Kinetic energy
m = Mass of the car and passengers = 1088 kg
v = Speed of the car at the bottom of the hill = 33 m/s
Plugging in the values:
KE = 1/2 * 1088 * (33)^2
KE = 1/2 * 1088 * 1089
KE = 592,416 Joules
Therefore, the kinetic energy of the car at the bottom of the hill is 592,416 Joules.