A roller coaster is at the top of a 62 meter hill the car and its passengers have a total mass of 1,088 kilograms. by the time the car reaches the bottom of the hill its speed is 74 miles per hour(33 meters per second) how much kinetic energy does the car have at the bottom of the hill
17,952j
592,416j
1,184,832j
2,978,944j
2,978,944j
To calculate the kinetic energy of the car at the bottom of the hill, we need to use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
First, convert the speed from miles per hour to meters per second:
74 miles per hour = 74 * 1609.34 meters per hour (since 1 mile = 1609.34 meters)
= 118,907.16 meters per hour
= (118,907.16 meters per hour) / (3600 seconds per hour)
≈ 33 meters per second
Now, substitute the values into the formula:
Kinetic Energy = (1/2) * 1088 kg * (33 m/s)^2
= (1/2) * 1088 kg * (1089 m^2/s^2)
≈ 595,296 joules
The closest option to this value is 592,416 joules, so that would be the answer.
To find the kinetic energy of the roller coaster at the bottom of the hill, we can use the formula:
Kinetic Energy = 1/2 * mass * velocity^2.
First, let's convert the speed from miles per hour to meters per second:
74 miles per hour = 33 meters per second.
Now, we can calculate the kinetic energy:
Kinetic Energy = 1/2 * mass * velocity^2
= 1/2 * 1088 kg * (33 m/s)^2
= 1/2 * 1088 kg * 1089 m^2/s^2
= 594,432 J.
Therefore, the kinetic energy of the roller coaster at the bottom of the hill is approximately 594,432 joules.