A carnival game involves drowning two bills from a bag. There are seven $1 bills, three $5 bills, and two $10 bills. What is the probability of drawing two $10 bills if the events are independent?
First, we need to determine the total number of bills in the bag. There are 7 + 3 + 2 = 12 bills in total.
The probability of drawing a $10 bill on the first draw is 2/12 = 1/6.
Since the events are independent, the probability of drawing another $10 bill on the second draw is also 2/12 = 1/6.
To find the probability of both events happening, we multiply the probabilities of each event occurring:
(1/6) * (1/6) = 1/36
Therefore, the probability of drawing two $10 bills if the events are independent is 1/36.