A girl standing on top of a roof Throws a rock at 30m/s at an angle 30 degrees below the horizontal is the roof top is 50m high how far from the base of the building with the rock land The answer is 52.3
To solve this problem, we can break down the initial velocity of the rock into its horizontal and vertical components.
The horizontal component of the velocity is given by: Vx = 30 * cos(30) = 26.0 m/s
The vertical component of the velocity is given by: Vy = 30 * sin(30) = 15.0 m/s
Next, we can calculate the time it takes for the rock to reach the ground by using the vertical motion equation:
h = Vy * t + (1/2) * g * t^2
50 = 15 * t + (1/2) * 9.81 * t^2
Solving for t, we get t = 3.19 seconds
Finally, we can calculate the horizontal distance the rock travels by using the horizontal motion equation:
D = Vx * t
D = 26.0 * 3.19
D = 52.3 meters
Therefore, the rock will land 52.3 meters from the base of the building.