A girl standing on top of a roof Throws a rock at 30m/s at an angle 30 degrees below the horizontal is the roof top is 50m high how far from the base of the building with the rock land
The answer is 52.3
To solve this problem, we can break down the initial velocity of the rock into horizontal and vertical components.
The initial vertical velocity (Vy) is given by:
Vy = V * sin(theta)
Vy = 30 m/s * sin(30)
Vy = 15 m/s
The initial horizontal velocity (Vx) is given by:
Vx = V * cos(theta)
Vx = 30 m/s * cos(30)
Vx = 26 m/s
Next, we can calculate the time it takes for the rock to hit the ground using the formula:
t = 2 * Vy / g
t = 2 * 15 / 9.8
t = 3.06 seconds
Now, we can calculate the horizontal distance the rock will travel by using the formula:
dx = Vx * t
dx = 26 m/s * 3.06 s
dx = 79.6 m
Therefore, the rock will land 79.6 meters away from the base of the building. However, since the roof is 50 meters high, we need to subtract this height from the horizontal distance to find the final answer:
dx = 79.6 m - 50 m
dx = 29.6 m
So, the rock will land approximately 29.6 meters away from the base of the building.