A sample of helium gas has a volume of 4.5 L at a pressure of 4.0 atm. The temperature and the number of gas particles do not change.
Part 1 of 2
What is the volume of gas (in L) at 26.6 atm? Be sure your answer has the correct number of significant figures.
L
X
Using Boyle's Law, we can set up the equation:
P1V1 = P2V2
(4.0 atm)(4.5 L) = (26.6 atm)(V2)
V2 = (4.0 atm)(4.5 L) / 26.6 atm
V2 = 0.675 L
Therefore, the volume of gas at 26.6 atm is 0.675 L.